The electrode pptenticals for ` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) ` and ` Cu^+ (aq) + e^- rarr Cu (s)` are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(cu^(2+)//Cu)^@` will be.A. 0.500 VB. 0.325 VC. 0.650 VD. 0.150 V

The electrode pptenticals for ` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) ` a

1.	The electrode pptenticals for ` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) ` and ` Cu^+ (aq) + e^- rarr Cu (s)` are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(cu^(2+)//Cu)^@` will be.A. 0.500 VB. 0.325 VC. 0.650 VD. 0.150 V
Answer» Correct Answer - B `Cu_((aq))^(2+) + e^(-) to Cu_((aq))^(+) , E_(1)^(@) = 0.15 V` `Cu_((aq))^(+) + e^(-) to Cu_((s)) , E_(2)^(@) = 0.50 V` `Cu^(2+) + 2e^(-) to Cu` Now , `Delta G^(@) = Delta G_(1)^(@) + Delta G_(2)^(@)` or , `- n FE^(@) =-n_(1) FE_(1)^(@) - n_(2) FE_(2)^(@)` or , `E^(@) = (n_(1) E_(1)^(@) + n_(2) E_(2)^(@))/(n) = (1 xx 0.15+ 1 xx 0.50)/(2) = 0.325` V

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The electrode pptenticals for ` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) ` and ` Cu^+ (aq) + e^- rarr Cu (s)` are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(cu^(2+)//Cu)^@` will be.A. 0.500 VB. 0.325 VC. 0.650 VD. 0.150 V

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