The electron in a hydrogen atom makes a transition `n_(1) rarr n_(2)`, where `n_(1)` and `n_(2)` are the principle quantum numbers of the two states. Assume the Bohr model to be valid. The time period of the electron in the initial state is eight times that in the final state. the possible values of `n_(1)` and `n_(2)` areA. `n_(1) = 4, n_(2) = 2`B. `n_(1) = 8, n_(2) = 2`C. `n_(1) = 8, n_(2) = 1`D. `n_(1) = 6, n_(2) = 3`

The electron in a hydrogen atom makes a transition `n_(1) rarr n_(2)`,

1.	The electron in a hydrogen atom makes a transition `n_(1) rarr n_(2)`, where `n_(1)` and `n_(2)` are the principle quantum numbers of the two states. Assume the Bohr model to be valid. The time period of the electron in the initial state is eight times that in the final state. the possible values of `n_(1)` and `n_(2)` areA. `n_(1) = 4, n_(2) = 2`B. `n_(1) = 8, n_(2) = 2`C. `n_(1) = 8, n_(2) = 1`D. `n_(1) = 6, n_(2) = 3`
Answer» Correct Answer - A::D Time period, `T_(n)=(2pi r_(n))/v_(n)` (in `n^(th)` state) i.e. `T_(n) prop r_(n)/v_(n)` But `r_(n) prop n^(2)` and `v_(n) prop 1/n` Therefore, `T_(n) prop n^(3)` given `T_(n1)=8T_(n2)` Hence, `n_(1)=2n_(2)`

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