The electron of hydrogen atom moves along a circular path of radius `0*5xx10^(-10)m` (i) with a speed of `4*0xx10^6ms^-1`. (ii) with a frequency `6*8xx10^(15)Hz`. Calculate the magnetic field produced at the centre of the circular path. `(e=1*6xx10^(-19)C)`.

The electron of hydrogen atom moves along a circular path of radius `0

1.	The electron of hydrogen atom moves along a circular path of radius `05xx10^(-10)m` (i) with a speed of `40xx10^6ms^-1`. (ii) with a frequency `68xx10^(15)Hz`. Calculate the magnetic field produced at the centre of the circular path. `(e=16xx10^(-19)C)`.
Answer» Correct Answer - `256T`, `134T` (i) `T=2pi r//v` and `i=e/T=(ev)/(2pir)` (ii) `i=ev` Now use, `B=(mu_0)/(4pi)(2pi i)/(r)=(mu_0)/(4pi)(2pi)/(r)ev`

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The electron of hydrogen atom moves along a circular path of radius `0*5xx10^(-10)m` (i) with a speed of `4*0xx10^6ms^-1`. (ii) with a frequency `6*8xx10^(15)Hz`. Calculate the magnetic field produced at the centre of the circular path. `(e=1*6xx10^(-19)C)`.

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The electron of hydrogen atom moves along a circular path of radius `05xx10^(-10)m` (i) with a speed of `40xx10^6ms^-1`. (ii) with a frequency `68xx10^(15)Hz`. Calculate the magnetic field produced at the centre of the circular path. `(e=16xx10^(-19)C)`.