1.

The Electronic configuration of `Gd^(2+)` is ( atomic no. of Gd is 64)A. `[Xe] 4f^(7)`B. `[Xe] 4f^(7) 5d^(1)`C. `[Xe]4f^(8)`D. `[Xe] 4f^(7)5d^(1) 6s^(2)`

Answer» `Gd(64) =[Xe] 4f^(7)5d^(1) 6s^(2)`
`:.Gd^(2+) = [ Xe] 4f^(7)5d^(1)`


Discussion

No Comment Found

Related InterviewSolutions