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The electronic configuration of given speices `(X)` is `1s^(2), 2s^(2)2p^(6), 3s^(2)3p^(6)3d^(5), 4s^(1)`. This can be itsA. Cationic form `X^(o+)`B. Anionic form `X^(ɵ)`C. Excited stateD. Ground state |
Answer» Correct Answer - A::D According to electronic configuration, the element is `Cr (Z = 24)`. Valence electronic configuration of `Cr` in ground state `= [Ar]3d^(4)4s^(1)`. Valence electronic confugration of `Cr` in excited state `= [Ar]3d^(5)4s^(1)`. |
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