1.

The electronic configuration of the outer most shell of the most electronegative element is :A. `2s^(2)2p^(5)`B. `3s^(2)3p^(5)`C. `4s^(2)4p^(5)`D. `5s^(2)5p^(5)`

Answer» Correct Answer - A
a) The electronic configuration represents
`2s^(2)2p^(5)`= fluorine= most electronegative element.
`3s^(2)3p^(5)` = chlorine.
`4s^(2)4p^(5)`=bromine
`5s^(2)5p^(5)`= iodine.


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