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The electronic configuration of the outer most shell of the most electronegative element is :A. `2s^(2)2p^(5)`B. `3s^(2)3p^(5)`C. `4s^(2)4p^(5)`D. `5s^(2)5p^(5)` |
Answer» Correct Answer - A a) The electronic configuration represents `2s^(2)2p^(5)`= fluorine= most electronegative element. `3s^(2)3p^(5)` = chlorine. `4s^(2)4p^(5)`=bromine `5s^(2)5p^(5)`= iodine. |
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