1.

The electrostatic force on a small sphere of charge 0.4 µC due to another small sphere of charge –0.8 µC in the air is 0.2 N.(a) What is the distance between the two spheres?(b) What is the force on the second sphere due to the first?

Answer»

(a) Given,

The charge on 1st sphere (q) and 2nd sphere (q2) is 0.4 µC or 0.4 × 10-6 C and -0.8 × 10-6C respectively.

The electrostatic force on the 1st sphere is given by F = 0.2N.

Electrostatic force between the spheres is given by the relation :

F = 1/4πϵo​ * q1q2/r2

Here,

ϵo​ = permittivity of free space and,

1/4πϵo​ = 9 × 109 Nm2C-2

r2 = 1/4πϵo ​​* q1​q2/F​​

= 0.4*10-6*8*10-6*9*109 / 0.2  = 144*10-4

r = ​√144 x 10-4 = 12 x 10-2 = 0.12m

Therefore, the distance between the two spheres = 0.12 m

(b) Since the spheres have opposite charges, the force on the second sphere due to the first sphere will also be equal to 0.2N.



Discussion

No Comment Found