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The electrostatic potential due to the charge configuration at point P as shown in figure for bltlta is A. `(2q)/(4piepsilon_0a)`B. `(2qb^2)/(4piepsilon_0a^3)`C. `(qb^2)/(4piepsilon_0a^3)`D. zero |
Answer» Correct Answer - C `V_p=2(1/(4piepsilon_0)q/a)-2[1/(4piepsilon_0).q/sqrt(b^2+a^2)]` `=q/(4piepsilon_0a)[2-2(1+b^2/a^2)^(-1//2)]` Since `bltlta`,we can apply binoial expansion `:. V_p=q/(4piepsilon_0a)[2-2(1-b^2/(2a^2))]` =`(qb^2)/(4piepsilon_0a^3)` |
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