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The electrostatic potential inside a charged spherical ball is given by `phi=ar^2+b` where r is the distance from the centre and a, b are constants. Then the charge density inside the ball is:A. ` - 24 pi a varepsilon_0`B. `-6 a varepsilon_0`C. `-24 pi a varepsilon_0^r`D. `-6 a varepsilon_0r` |
Answer» Correct Answer - B | |