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The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:A. `0.16`B. `0.05`C. `0.1`D. ` 0.2` |
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Answer» Correct Answer - A `Delta T_(b) = (1000 xx 0.52 xx 13.44)/(13.44 xx 1000) xx (1+2 alpha) (because alpha = 1)` `= 0.052 xx 3 = 0.156` |
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