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The elevator can carry a maximum load of 2800 kg (elevator +passengers) is moving up with a constant speed of 2ms^(-1). The frictional force opposing the motion is 5000 N .Determine the minimum power delivered by the motorto the elevator in watts as well as in horse power . |
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Answer» <P> SOLUTION :`P = 99000 W, 132.7 HP` |
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