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The EMF of a cell formed by combining a particular electrode with standard calomel electrode is found to be 0.344 V and calomel electrode is found to act as cathode. If the same electrode is combined with standard hydrogen electrode, the EMF of the cell will be (Given standard reduction potential, `E_("calomel")^(@)=+0.244V`)A. 0.344VB. 0.244 VC. 0.588 VD. 0.100 V |
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Answer» Correct Answer - D `E_(cell)=E_("cathode")^(@)-E_("anode")^(@)` `0.344=E_("calomel")^(@)-E_(X)^(@)` `0.344=0.244-E_(X)^(@)` or `E_(X)^(@)=-0.100V` As `E_(H^(+)//H_(2))^(@)=0,E_(cell)^(@)` with SHE=0.100V. |
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