The EMF of a cell is related to the equilibrium constant of the cell reaction asA. In `k_(c)=(nFE_("cell")^(@))/(RT)`B. `k_(c)=(nFE_("cell")^(@))/(RT)`C. `E_("cell")^(@)=(RT)/(nF)` in `k_(c)`D. `k_(c)=(RT)/(nF)` in `E_("cell")^(@)`

The EMF of a cell is related to the equilibrium constant of the cell r

1.	The EMF of a cell is related to the equilibrium constant of the cell reaction asA. In `k_(c)=(nFE_("cell")^(@))/(RT)`B. `k_(c)=(nFE_("cell")^(@))/(RT)`C. `E_("cell")^(@)=(RT)/(nF)` in `k_(c)`D. `k_(c)=(RT)/(nF)` in `E_("cell")^(@)`
Answer» Correct Answer - A `E_("cell")^(@)=-nFE^(@)`

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The EMF of a cell is related to the equilibrium constant of the cell reaction asA. In `k_(c)=(nFE_("cell")^(@))/(RT)`B. `k_(c)=(nFE_("cell")^(@))/(RT)`C. `E_("cell")^(@)=(RT)/(nF)` in `k_(c)`D. `k_(c)=(RT)/(nF)` in `E_("cell")^(@)`

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