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The emf of a Daniel cell at 298K is E1:Zn/ZnSO4(0.01M)//CuSO4(1M)/Cu .When the concentration of ZnSO4 is 1M and that of CuSO4 is0.01M ,the emf changed to E2.What is the relationship between E1 and E2?Options:1)E1>E2. 2)E1 |
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Answer» The emf of a Daniel cell at 298K is E1:Zn/ZnSO4(0.01M)//CuSO4(1M)/Cu .When the concentration of ZnSO4 is 1M and that of CuSO4 is0.01M ,the emf changed to E2.What is the relationship between E1 and E2?Options:1)E1>E2. 2)E1 |
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