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The emf of a daniel cell is 1.08 V. When the terminals of the cells are connected to a ressitance of `3Omega`, the potential difference across the terminals is found to be 0.6 V. Then the internal resistance of the cell isA. `1.8Omega`B. `2.4Omega`C. `3.24Omega`D. `0.2Omega` |
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Answer» Correct Answer - B `r=((E-V)/(V))R` |
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