The EMF of cell Ni|Ni2+||Au3+|Au is: Given that E∘=−0.25V for Ni2+ – InterviewSolution

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1.	The EMF of cell Ni\|Ni2+\|\|Au3+\|Au is: Given that E∘=−0.25V for Ni2+\|Ni;E∘=1.5V for Au3+\|Au
Answer» The EMF of cell $N i \| N i^{2 +} \| \| A u^{3 +} \| A u$ is: Given that $E^{\circ} = - 0.25 V$ for $N i^{2 +} \| N i; E^{\circ} = 1.5 V$ for $A u^{3 +} \| A u$

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