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The emf of Daniel cell Zn(s) + Zn2+aq(1m) || Cu2+ | Cu(s) is equal to ………… (a) – 1.107 Volts (b) 1.107 Volts (c) 3.4 Volt (d) 7.6 Vol |
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Answer» (b) 1.107 Volts |
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