the emf of the cell at 25 degree celecius is Pt, H2 / HCl(C1) // HCl(C1)/ H2, Pt (2atm) (10atm)

the emf of the cell at 25 degree celecius is Pt, H2 / HCl(C1) // HCl(C

1.	the emf of the cell at 25 degree celecius is Pt, H2 / HCl(C1) // HCl(C1)/ H2, Pt (2atm) (10atm)
Answer» the emf of the cell at 25 degree celecius is Pt, H2 / HCl(C1) // HCl(C1)/ H2, Pt (2atm) (10atm)