The emf of the cell, `Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@)` for `Ni^(2+)//Ni =- 0.25` volt, `E^(@)` for `Ag^(+)//Ag = 0.80` volt] is given by : `[E^(@)` for `Ag^(+)//Ag = 0.80` volt]A. `-0.25 +0.80 = 0.55` voltB. `-0.25 -(+0.80) =- 1.05` voltC. `0 +0.80 -(-0.25)=+ 1.05` voltD. `-0.80 -(+0.25) =- 0.55` volt

The emf of the cell, `Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@)` for `N

1.	The emf of the cell, `Ni\|Ni^(2+)(1.0M)\|\|Ag^(+)(1.0M)\|Ag [E^(@)` for `Ni^(2+)//Ni =- 0.25` volt, `E^(@)` for `Ag^(+)//Ag = 0.80` volt] is given by : `[E^(@)` for `Ag^(+)//Ag = 0.80` volt]A. `-0.25 +0.80 = 0.55` voltB. `-0.25 -(+0.80) =- 1.05` voltC. `0 +0.80 -(-0.25)=+ 1.05` voltD. `-0.80 -(+0.25) =- 0.55` volt
Answer» Correct Answer - C `E_("cell")^(@)= E_("cathod")^(@)-E_("anode")^(@)=0.80 - (-0.25)= 1.05 V`

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What are elementary reactions ?

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