The emf of the cell, Pt|H2(1 atm),|H+ (0.1 M, 40 mL)||Ag+(0.8 mM)|Ag i – InterviewSolution

InterviewSolution

1.	The emf of the cell, Pt\|H2(1 atm),\|H+ (0.1 M, 40 mL)\|\|Ag+(0.8 mM)\|Ag is 0.9 V. Calculate the emf when 60 mL of 0.05 M NaOH is added to the anodic compartment.Given: 2.303RTF=0.06,log2=0.3
Answer» The emf of the cell, $P t \| H_{2} (1 atm), \| H^{+} (0.1 M, 40 mL) \| \| A g^{+} (0.8 mM) \| A g$ is $0.9 V$ . Calculate the emf when $60 mL$ of $0.05 M N a O H$ is added to the anodic compartment. Given: $\frac{2.303 R T}{F} = 0.06, log 2 = 0.3$

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