The emf of the cell `Zn|Zn^(2+)(1M)||Cu^(2+)|Cu(1M)` is 1.1V. If the standard reduction potential of `Zn^(2+)|Zn` is -0.78V, what is the oxidation potential of `Cu|Cu^(2+)`?A. `+ 1.86` VB. `0.32` VC. `-0.32` VD. `1.86` V

The emf of the cell `Zn|Zn^(2+)(1M)||Cu^(2+)|Cu(1M)` is 1.1V. If the s

1.	The emf of the cell `Zn\|Zn^(2+)(1M)\|\|Cu^(2+)\|Cu(1M)` is 1.1V. If the standard reduction potential of `Zn^(2+)\|Zn` is -0.78V, what is the oxidation potential of `Cu\|Cu^(2+)`?A. `+ 1.86` VB. `0.32` VC. `-0.32` VD. `1.86` V
Answer» Correct Answer - C `E_("cell") = [E_(OP_(Zn))^(@) + E_(RP _(Cu))^(@)] + (0.0592)/(2) log _(10) ([Cu^(2+)])/([Zn^(2+)])` `therefore 1.1 = 0.78 + E_(RP_(Cu))^(@) + (0.0592)/(2) log _(10) (1) (because log 1 = 0)` `therefore E_(RP)^(@) (Cu^(2+) \| Cu) = 1.1 - 0.78 = 0.32` `therefore E_(OP)^(@) (Cu\|Cu^(2+)) = -0.32`

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The emf of the cell `Zn|Zn^(2+)(1M)||Cu^(2+)|Cu(1M)` is 1.1V. If the standard reduction potential of `Zn^(2+)|Zn` is -0.78V, what is the oxidation potential of `Cu|Cu^(2+)`?A. `+ 1.86` VB. `0.32` VC. `-0.32` VD. `1.86` V

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