The emf of the following cell at 25°C is equal to 0.34v. Calculate th – InterviewSolution

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The emf of the following cell at 25°C is equal to 0.34v. Calculate the reduction potential of copper electrode. Pt(s) | H2(g,1atm) | H+ (aq,1M) || Cu2+ (aq,1M) | Cu(s)

Answer»

SHE Value is zero

E_cell° = E_R° – E_L°

= 0.34 – 0 = 0.34V

The reduction potential of copper electrode = 0.34V

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