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| 1. |
The emf `varepsilon` of a Cu-Fe thermocouple varies with the temperature `theta` of the hot junction (cold junction at `0^(@)C` ), as `varepsilon(mu V)=14 theta-0.02 theta^(2)` Determine the neutral temperature. |
| Answer» At neutral temperature `(dE)/(dtheta)=0 therefore 14-2(0.02theta_(n))=0rArr theta_(n)=(14)/(0.04)=350^(@)C` | |