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The empirical formula and molecular mass of a compound are `CH_(2)O` and 180 g respectively. What will be the molecular formula of the compound ?A. `C_9H_18O_9`B. `CH_2O`C. `C_6H_12O_6`D. `C_2H_4O_2`

Answer» `n=("Molecular mass")/("Empirical formula mass") = 180/30=6 ( therefore " Empirical formula mass of " CH_2O=30)`
`therefore " Molecular formula " = 5xx CH_2O=C_6H_12O_6`


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