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The empirical formula of a compound is `CH_(2)`. IF one mole of the compound has a mass of `42 g`, its molecular formula isA. `CH_(2)`B. `C_(3)H_(6)`C. `C_(2)H_(2)`D. `C_(3)H_(8)` |
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Answer» Correct Answer - B Molecular formula `= n` (Empirical formula) `n = ("Molecular mass")/("Empirical formula mass") = (42 u)/(14 u) = 3` `:. M.F. = 3(CH_(2)O) = C_(3)H_(6)O_(3)` |
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