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The empirical formula of a compound is `CH_(2)O`. If its vapour density is 90, find out the molecular formula of the compound. |
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Answer» Empirical formula=`CH_(2)O` Empirical formula weight = `= 12 + (1xx2) + 16 = 30` Vapour density (VD) = 90 Molecular wieght =`VD xx 2 = 180` Molecular formula = `("empirical formula")_(n)` `n=("Molecular weight")/("Empirical formula weight")=180/30 = 6` Thus, molecular formula = `(CH_(2)O)_(6) = C_(6)H_(12)O_(6)` In stoichiometry, we find out the quantitative relationship between the reactants and the products on the basis of balanced chemical equation. |
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