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The empirical formula of an organic compound carbon & hydrogen is `CH_(2)` The mass of `1"litre"` of organic gas is exactly equal to mass of 1 litre `N_(2)` therefore molecular formula of organic gas is . |
Answer» Empirical Mass of `CH_(3)=12+2=14` `because` Mass of 1 litre of organic gas = Mass of 1 litre of `N_(2)` Since V,P,T, n are same. Therefore PV=`(m)/(M)RT` implies that molar mass should also be same. `therefore ` Molecular mass of organic compound will be 28 g `n=("Molecular mass")/("Empirical mass")=(28)/(14)=2` So molecular formula `=2xxCH_(2) =C_(2)H_(4)` |
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