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The ends of a stretched wire of length `L` are fixed at `x = 0 and x = L`. In one experiment, the displacement of the wire is `y_(1) = A sin(pi//L) sin omegat` and energy is `E_(1)` and in another experiment its displacement is `y_(2) = A sin (2pix//L ) sin 2omegat` and energy is `E_(2)`. ThenA. `E_(2) = E_(1)`B. `E_(2) = 2E_(1)`C. `E_(2) = 4E_(1)`D. `E_(2) = 16E_(1)` |
| Answer» Correct Answer - C | |