The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is y1 = A sin (πxL) sinωt and energy is E1 and in another experiment its displacement is y2 = A sin(2πxL)sin 2 ωt and energy is E2. Then

The ends of a stretched wire of length L are fixed at x = 0 and x = L.

1.	The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is y1 = A sin (πxL) sinωt and energy is E1 and in another experiment its displacement is y2 = A sin(2πxL)sin 2 ωt and energy is E2. Then
Answer» The ends of a stretched wire of length $L$ are fixed at $x$ = 0 and $x$ = $L$ . In one experiment the displacement of the wire is $y_{1}$ = $A s i n (\frac{π x}{L}) s i n ω t$ and energy is $E_{1}$ and in another experiment its displacement is $y_{2}$ = $A s i n (\frac{2 π x}{L}) s i n 2 ω t$ and energy is $E_{2}$ . Then

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The ends of a stretched wire of length L are fixed at x = 0 and x = L. In one experiment the displacement of the wire is y1 = A sin (πxL) sinωt and energy is E1 and in another experiment its displacement is y2 = A sin(2πxL)sin 2 ωt and energy is E2. Then

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