The ends of a stretched wire of length L are fixed at x=0 and x=L. If in an experiment, the displacement of the wire is y1=Asin(πxL)sinωt and energy is E1 and in another experiment, its displacement is y2=Asin(2πxL)sin2ωt and energy is E2, then[Assume, there is no energy loss at the ends of the stretched wire]

The ends of a stretched wire of length L are fixed at x=0 and x=L. If

1.	The ends of a stretched wire of length L are fixed at x=0 and x=L. If in an experiment, the displacement of the wire is y1=Asin(πxL)sinωt and energy is E1 and in another experiment, its displacement is y2=Asin(2πxL)sin2ωt and energy is E2, then[Assume, there is no energy loss at the ends of the stretched wire]
Answer» The ends of a stretched wire of length $L$ are fixed at $x = 0$ and $x = L$ . If in an experiment, the displacement of the wire is $y_{1} = A sin (\frac{π x}{L}) sin ω t$ and energy is $E_{1}$ and in another experiment, its displacement is $y_{2} = A sin (\frac{2 π x}{L}) sin 2 ω t$ and energy is $E_{2}$ , then [Assume, there is no energy loss at the ends of the stretched wire]

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