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The energy loss due to friction (Ef) in a circular conduit (on the basis of per unit mass) is given by_____(a) Ef = 4fLv̅²/2D(b) Ef = 8fLv̅²/2D(c) Ef = 4fLv̅³/2D(d) Ef = 4fLv̅²/DI had been asked this question by my college professor while I was bunking the class.The query is from Effects of Friction and Velocity Distribution in section Pouring – Gating Design, Melting Furnaces, Melting and Casting Quality of Casting-Forming-Welding I

Answer»

The correct ANSWER is (a) Ef = 4fLv̅²/2D

For explanation I would say: Ef = 4fLv̅²/2D is the energy loss DUE to friction in a circular conduit. The frictional losses are PRESENT due to SUDDEN contraction or enlargement of the flow cross-sections. Where, v̅ = Average velocity, D = Diameter of the conduit, L = Length of the conduit and f = friction FACTOR.



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