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The energy loss due to friction (Ef) in a circular conduit (on the basis of per unit mass) is given by_____(a) Ef = 4fLv̅²/2D(b) Ef = 8fLv̅²/2D(c) Ef = 4fLv̅³/2D(d) Ef = 4fLv̅²/D |
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Answer» The correct answer is (a) Ef = 4fLv̅²/2D For explanation I would say: Ef = 4fLv̅²/2D is the energy loss due to friction in a circular conduit. The frictional losses are present due to sudden contraction or enlargement of the flow cross-sections. Where, v̅ = Average velocity, D = Diameter of the conduit, L = Length of the conduit and f = friction factor. |
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