1.

The energy of a photon is given as `3.03xx10^(-19)J`. The wavelength of the photon isA. 6.56 nmB. 65.6 nmC. 0.656 nmD. 656 nm

Answer» Correct Answer - D
`E=(hc)/lamdaorlamda=(hc)/E
lamda=(6.626xx10^(-34)Jsxx3xx10^(8)ms^(-1))/(3.03xx10^(-19)J)
6.56xx10^(-7)m or 656nm`


Discussion

No Comment Found

Related InterviewSolutions