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The energy of a photon is given as `3.03xx10^(-19)J`. The wavelength of the photon isA. 6.56 nmB. 65.6 nmC. 0.656 nmD. 656 nm |
Answer» Correct Answer - D `E=(hc)/lamdaorlamda=(hc)/E lamda=(6.626xx10^(-34)Jsxx3xx10^(8)ms^(-1))/(3.03xx10^(-19)J) 6.56xx10^(-7)m or 656nm` |
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