InterviewSolution
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InterviewSolution
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The energy of a system as a function of time `t` is given as `E(t) = A^(2)exp(-alphat)`, `alpha = 0.2 s^(-1)`. The measurement of `A` has an error of `1.25%`. If the error In the measurement of time is `1.50%`, the percentage error in the value of `E(t)` at t = 5 s` is |
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Answer» Correct Answer - `4` `E(t) = A^(2) e^(- alpha t)` In `E = 2 In A - alpha t` `:. (Delta E)/(E) xx 100 = 2 (Delta A)/( A) xx 100 - alpha t xx 100` (i) For time : `(Delta t)/(t) xx 100 = 1.5` At `t = 5 s, Delta t = ( 1.5 xx 5 )/( 100) = ( 7.5)/( 100)` Using Eq(i) % error in `E = 2 xx ( 1.25) + alpha xx ( 7.5)/(100) xx 100` `= 2.5 + 1.5 = 4` |
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