InterviewSolution
Saved Bookmarks
| 1. |
The energy of an a-particle is `6.8xx10^(-18)J` . What will be the wave length associated with it ? Given : `h=6.62xx10^(-34)Js, 1 "amu"=1.67xx10^(-27)`kg. |
|
Answer» `lambda=(h)/(sqrt(2mE))" " ," " E=6.8xx10^(-18)J=6.8xx10^(-18)kgm^(2)s^(-2)` `h=6.62xx10^(-34)Js=6.62xx10^(-34)kgm^(2)s^(-1)` `m(alpha-"particle")=4"amu"=4xx1.67xx10^(-27)kg` `lambda=((6.62xx10^(-34)"kg "m^(2)s^(-1)))/([2xx(6.8xx10^(-18)"kg "^(2)s^(-2))xx(4xx1.67xx10^(-27)kg)]^(1//2))=0.22xx10^(-11)m`. |
|