1.

The energy of emitted photoelectrons from a metal is 0.9 eV and energy of incident photon is 3.1 eV then the work function of a metal is(a) 4.0 eV(b) 2.2 eV(c) 3.0 eV(d) 3.1 eV

Answer»

Correct option is (b) 2.2 eV

E = ϕ + KEmax

ϕ = 3.1 - 0.9

ϕ = 2.2 ev



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