the energy of photon is equal to the kineticenergy of a porton,If lambda_1 is the De-Broglie wavelengthof a proton,lambda_2 the wavelength associated with the proton and if the energt of the protonis E, then (lamda_1//lambda_2) is proportional to

the energy of photon is equal to the kineticenergy of a porton,If lamb

1.	the energy of photon is equal to the kineticenergy of a porton,If lambda_1 is the De-Broglie wavelengthof a proton,lambda_2 the wavelength associated with the proton and if the energt of the protonis E, then (lamda_1//lambda_2) is proportional to
Answer» `lambda_1+ lambda_2` = `lambda_3` `(1)/(lambda_3) = 1/(lambda_1) + 1/(lambda_2)` `lambda_3 = SQRT(lambda_1 lambda_2)` `(2)/(lambda_3) = 1/(lambda_1) + (1)/(lambda_2)` SOLUTION :`(E_R - E_Q) + (E_Q-E_P) = (E_R - R_P)` `1/(lambda_1) + 1/(lambda_2) = 1/(lambda_3)`