The energy of photon of radiation having wavelength 300 nm

1.	The energy of photon of radiation having wavelength 300 nm
Answer» Photons\xa0are electrically neutral.\xa0Photons\xa0have no mass, but they have\xa0energy\xa0E = hf = hc/λ. Here h = 6.626*10-34\xa0Js is a universal constant called Planck\'s constant. The\xa0energy\xa0of each\xa0photon\xa0is inversely proportional to the\xa0wavelength\xa0of the associated EM wave.\xa0The energy associated with a single photon is given by\xa0E = h ν\xa0, where\xa0E is\xa0the energy (SI units of\xa0J), h is\xa0Planck\'s constant\xa0(h = 6.626 x 10–34\xa0J\xa0s), and ν is the frequency of the radiation (SI units of s–1\xa0or Hertz, Hz)\xa0

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