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The energy radiated from a black-body at a temperature of 727°C is E. By what factor the radiated energy shall increase if the temperature is raised to 2227°C ? |
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Answer» E2/E1 = [ T2/T1]4 = [(2227 + 273) / (727 + 273)]4 = [2500/1000]4 = 39 |
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