The energy required to charge a parallel plate condenser of plate separtion `d` and plate area of cross-section `A` such that the unifom field between the plates is `E` isA. `(1)/(2)epsilon_(0)E^(2)//Ad`B. `epsilon_(0)E^(2)//Ad`C. `epsilon_(0)E^(2)Ad`D. `(1)/(2)epsilon_(0)E^(2)Ad`

The energy required to charge a parallel plate condenser of plate sepa

1.	The energy required to charge a parallel plate condenser of plate separtion `d` and plate area of cross-section `A` such that the unifom field between the plates is `E` isA. `(1)/(2)epsilon_(0)E^(2)//Ad`B. `epsilon_(0)E^(2)//Ad`C. `epsilon_(0)E^(2)Ad`D. `(1)/(2)epsilon_(0)E^(2)Ad`
Answer» Correct Answer - C Energy given by the cell, `E=CV^(2)` Here, C = capacitiance of condenser `=(Aepsilon_(0))/(d)` V = potential across the plates = Ed Therefore, `E=((Aepsilon_(0))/(d))(Ed)^(2)=Aepsilon_(0)E^(2)d`

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The energy required to charge a parallel plate condenser of plate separtion `d` and plate area of cross-section `A` such that the unifom field between the plates is `E` isA. `(1)/(2)epsilon_(0)E^(2)//Ad`B. `epsilon_(0)E^(2)//Ad`C. `epsilon_(0)E^(2)Ad`D. `(1)/(2)epsilon_(0)E^(2)Ad`

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