InterviewSolution
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InterviewSolution
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The energy required to charge a parallel plate condenser of plate separtion `d` and plate area of cross-section `A` such that the unifom field between the plates is `E` isA. `1/2epsi_(0)E^(2)//Ad`B. `epsi_(0)E^(2)//Ad`C. `epsi_(0)E^(2)Ad`D. `1/2epsi_(0)E^(2)Ad` |
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Answer» Correct Answer - C Energy given by the cell `E=CV^(2)` Here, C = capacitance of condenser `=(Aepsi_(0))/(d)` V= potential difference across the plates =Ed Therefore, `E=((Aepsi_(0))/(d))(Ed)^(2)=Aepsi_(0)E^(2)d` |
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