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The energy stored in a charged capacitor of capa city 25 µF is 4J. Find the charge on its plate. |
Answer» Data: C = 25 pF = 25 × 10-12 F, U = 4 J U = \(\cfrac12\)\(\cfrac{Q^2}C\) ∴ The charge, Q = \(\sqrt{2UC}\) = \(\sqrt{2\times4\times25\times10^{-12}}\) = 1.414 x 10-5 C (= 14.14 µC) |
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