InterviewSolution
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InterviewSolution
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The enolic form of acetone containsA. 9 sigma bonds, 1 pi bond and 2 lone pairsB. 8 sigma bonds, 2 pi bond and 2 lone pairsC. 10 sigma bonds, 1 pi bond and 1 lone pairsD. 9 sigma bonds, 2 pi bonds and 1 lone pair |
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Answer» Correct Answer - A Enolic form of acetone is `underset("Enolic form")(CH_(2)=overset(OH)overset(|)(C)-CH_(3)) " " underset("Keto form")(CH_(3)-overset(O)overset(||)(C)-CH_(3))` `H underset(sigma)-overset(H)overset(|sigma)(C)underset(pi)overset(sigma)=overset(overset(..sigma)( :O-H))overset(|sigma)(Cunderset(sigma)-)underset(H)underset(|sigma)overset(H)overset(|sigma)(C)overset(sigma)-H`, Hence, `sigma` -bonds = 9, `pi` -bonds = 1, lone pair =2 |
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