The enthalpy change `(DeltaH)` for the reaction, `N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) " is "-92.38 kJ` at 298 K. The internal energy change `DeltaU` at 298 K isA. `-92.38 kJ`B. `-87.42 kJ`C. `-97.34 kJ`D. `-89.9 kJ`

The enthalpy change `(DeltaH)` for the reaction, `N_(2)(g) + 3H_(2)(g)

1.	The enthalpy change `(DeltaH)` for the reaction, `N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) " is "-92.38 kJ` at 298 K. The internal energy change `DeltaU` at 298 K isA. `-92.38 kJ`B. `-87.42 kJ`C. `-97.34 kJ`D. `-89.9 kJ`
Answer» Correct Answer - B `DeltaH=DeltaU+Deltan_(g)RT` `Deltan_(g)=-2`.

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The enthalpy change `(DeltaH)` for the reaction, `N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) " is "-92.38 kJ` at 298 K. The internal energy change `DeltaU` at 298 K isA. `-92.38 kJ`B. `-87.42 kJ`C. `-97.34 kJ`D. `-89.9 kJ`

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