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The enthalpy of formation of `H_(2)O(l)` is -280.70 kJ/mol and enthalpy of neutralisation of a strong acid and strong base is -56.70 kJ/mol. What is the enthalpy of formation of `OH^(-)` ions?A. `+229.70KJ`B. `-229.70KJ`C. `+226.70KJ`D. `-22.670KJ` |
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Answer» Correct Answer - A `H^(+)(aq)+OH^(-)(aq)rarrH_(2)O(l),DeltaH=-56.07KJ` `DeltaH=DeltaH_(f)(H_(2)O)-[Delta_(f)(H^(+))+DeltaH_(f)(OH)^(-)]` `[:. DeltaH_(f)(H)^(+)=0]-56.07=-285.77-(0+x)` `:. x=-285.77+56.07=-229.70KJ` |
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