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The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at `0^(@)C` isA. 10.52 cal/(mol K)B. 21.04 cal/(mol K)C. 5.260 cal/(mol K)D. 0.526 cal/(mol K) |
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Answer» Correct Answer - C `DeltaS=(DeltaH)/(T)=(1.435xx10^(3))/(273)=5.260 cal//"molK"` |
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