The enthalpy of neutralization of HCl and NaOH is −57 kJ mol−1. Th – InterviewSolution

InterviewSolution

1.	The enthalpy of neutralization of HCl and NaOH is −57 kJ mol−1. The heat evolved at constant pressure (in kJ) when 0.5 mole of H2SO4 react with 0.75 mole of NaOH is equal to
Answer» The enthalpy of neutralization of $H C l$ and $N a O H$ is $- 57 k J m o l^{- 1}$ . The heat evolved at constant pressure (in kJ) when $0.5 m o l e$ of H2SO4 react with $0.75 m o l e$ of $N a O H$ is equal to

Discussion

No Comment Found

Related InterviewSolutions

Calculate the enthalpy change (△H) of the following reaction 2C2H2(g)+5O2(g)→4CO2(g)+2H2O(g) given average bond enthalpies of various bonds, i.e., C−H,C≡C,O=O,C=O,O−H as 414, 814 499, 724 and 640 kJ mol−1 respectively.
The order of strength of hydrogen bond is:
Which of the following is identified by carbyl amine reaction
Ground state electronic configuration of nitrogen atom can be represented by
Chlorination of isobutane mainly gives
Calculate the number of photons emitted per second by a 10 W sodium vapour lamp. Assume that 60% of the consumed energy is converted into light. Wavelength of sodium light is 662 nm.(Given that h=6.62×10−34 J s)
In C+H2O→CO+H2H2O acts as
Among the following, the molecule with the highest dipole moment is [IIT-JEE (Screening) 2003]
Lead nitrate on heating (Decomposition) gives
Strength of acidity is in order:

Related Topics

Physics

Mathematics

Chemistry

Biology

Recent Visits