1.

The enthalpy of neutralization of HCN by NaOH is `- 12.13 kJ mol^(-1)`. The enthalpy of ionisation of HCN will beA. 4.519 kJB. 54.10 kJC. 451.9 kJD. 45.19 kJ

Answer» Correct Answer - D
`-57.4+x=-12.13`
`x=45.2`.


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