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The enthalpy of solution of sodium chloride is 4 kJ `mol^(-1)` and its enthalpy of hydration of ions is `-784kJ mol^(-1)`. Then the lattice enthalpy of NaCl `("in kJ mol"^(-1))` isA. `+788`B. `+4`C. `+398`D. `+780` |
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Answer» Correct Answer - A `DeltaH_("sol")=DeltaH_("lattice")+DeltaH_("hydration")` |
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