The equation for the fundamental standing sound wave in a tube that is closed at both ends if the tube is `80 cm` long and speed of the wave is `330 m//s` is (assume that amplitude of wave at antinode to be `s_(0)`)A. `y = s_(0) cos (3.93 t) sin (1295 x)`B. `y = s_(0) sin (7.86 t) cos (1295 x)`C. `y = s_(0) cos (7.86 t) sin (1295 x)`D. `y = s_(0) cos (1295 t) sin (3.93 x)`

The equation for the fundamental standing sound wave in a tube that is

1.	The equation for the fundamental standing sound wave in a tube that is closed at both ends if the tube is `80 cm` long and speed of the wave is `330 m//s` is (assume that amplitude of wave at antinode to be `s_(0)`)A. `y = s_(0) cos (3.93 t) sin (1295 x)`B. `y = s_(0) sin (7.86 t) cos (1295 x)`C. `y = s_(0) cos (7.86 t) sin (1295 x)`D. `y = s_(0) cos (1295 t) sin (3.93 x)`
Answer» Correct Answer - D Since `f_(n) = n ((v)/( 2 L)) = n((330)/( 1.6)) = 206 n` `lambda_(n) = ( 2 L)/(n) = (1.6)/(n)` `{ L = (n lambda_(n))/(2)}` And the standing wave equation with nodes at both ends is `s = s_(0) sin(3.93 n x) cos (1295 n t)` For fundamental mode//frequency ` n = 1` `s = s_(0) = sin (3.93 x) cos (1295 t)`

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